(x+1)^2=((x-1)+5)(x-1)

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Solution for (x+1)^2=((x-1)+5)(x-1) equation: 



(x+1)^2=((x-1)+5)(x-1)

We move all terms to the left:

(x+1)^2-(((x-1)+5)(x-1))=0



We calculate terms in parentheses: -(((x-1)+5)(x-1)), so:

((x-1)+5)(x-1)



We calculate terms in parentheses: +((x-1)+5)(x-1), so:

(x-1)+5)(x-1

We get rid of parentheses

x+5)(x-1-1

We add all the numbers together, and all the variables

x+5)(x-2

Back to the equation:

+(x+5)(x-2)



We multiply parentheses ..

(+x^2-2x+5x-10)

We get rid of parentheses

x^2-2x+5x-10

We add all the numbers together, and all the variables

x^2+3x-10

Back to the equation:

-(x^2+3x-10)



We get rid of parentheses

-x^2+(x+1)^2-3x+10=0

We add all the numbers together, and all the variables

-1x^2-3x+(x+1)^2+10=0

We move all terms containing x to the left, all other terms to the right

-1x^2-3x+(x+1)^2=-10

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